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6(-1+x)=2(x+3)
We move all terms to the left:
6(-1+x)-(2(x+3))=0
We add all the numbers together, and all the variables
6(x-1)-(2(x+3))=0
We multiply parentheses
6x-(2(x+3))-6=0
We calculate terms in parentheses: -(2(x+3)), so:We get rid of parentheses
2(x+3)
We multiply parentheses
2x+6
Back to the equation:
-(2x+6)
6x-2x-6-6=0
We add all the numbers together, and all the variables
4x-12=0
We move all terms containing x to the left, all other terms to the right
4x=12
x=12/4
x=3
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