6(-11+4a)-2=4(1+12a)

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Solution for 6(-11+4a)-2=4(1+12a) equation: 



6(-11+4a)-2=4(1+12a)

We move all terms to the left:

6(-11+4a)-2-(4(1+12a))=0

We add all the numbers together, and all the variables

6(4a-11)-(4(12a+1))-2=0

We multiply parentheses

24a-(4(12a+1))-66-2=0



We calculate terms in parentheses: -(4(12a+1)), so:

4(12a+1)

We multiply parentheses

48a+4

Back to the equation:

-(48a+4)



We add all the numbers together, and all the variables

24a-(48a+4)-68=0

We get rid of parentheses

24a-48a-4-68=0

We add all the numbers together, and all the variables

-24a-72=0

We move all terms containing a to the left, all other terms to the right

-24a=72

a=72/-24

a=-3

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