6(-2+2m)+2m=-32+4m

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Solution for 6(-2+2m)+2m=-32+4m equation: 



6(-2+2m)+2m=-32+4m

We move all terms to the left:

6(-2+2m)+2m-(-32+4m)=0

We add all the numbers together, and all the variables

6(2m-2)+2m-(4m-32)=0

We add all the numbers together, and all the variables

2m+6(2m-2)-(4m-32)=0

We multiply parentheses

2m+12m-(4m-32)-12=0

We get rid of parentheses

2m+12m-4m+32-12=0

We add all the numbers together, and all the variables

10m+20=0

We move all terms containing m to the left, all other terms to the right

10m=-20

m=-20/10

m=-2

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