6(-2+6x)+8(4-2x)=7x+12x

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Solution for 6(-2+6x)+8(4-2x)=7x+12x equation: 



6(-2+6x)+8(4-2x)=7x+12x

We move all terms to the left:

6(-2+6x)+8(4-2x)-(7x+12x)=0

We add all the numbers together, and all the variables

6(6x-2)+8(-2x+4)-(+19x)=0

We multiply parentheses

36x-16x-(+19x)-12+32=0

We get rid of parentheses

36x-16x-19x-12+32=0

We add all the numbers together, and all the variables

x+20=0

We move all terms containing x to the left, all other terms to the right

x=-20

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