6(-2g-1)=-(13g2)

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Solution for 6(-2g-1)=-(13g2) equation:



6(-2g-1)=-(13g^2)
We move all terms to the left:
6(-2g-1)-(-(13g^2))=0
determiningTheFunctionDomain -(-13g^2)+6(-2g-1)=0
We multiply parentheses
-(-13g^2)-12g-6=0
We get rid of parentheses
13g^2-12g-6=0
a = 13; b = -12; c = -6;
Δ = b2-4ac
Δ = -122-4·13·(-6)
Δ = 456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{456}=\sqrt{4*114}=\sqrt{4}*\sqrt{114}=2\sqrt{114}$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{114}}{2*13}=\frac{12-2\sqrt{114}}{26} $
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{114}}{2*13}=\frac{12+2\sqrt{114}}{26} $

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