6(-3c-10)+9c=7c+6+6c

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Solution for 6(-3c-10)+9c=7c+6+6c equation: 



6(-3c-10)+9c=7c+6+6c

We move all terms to the left:

6(-3c-10)+9c-(7c+6+6c)=0

We add all the numbers together, and all the variables

6(-3c-10)+9c-(13c+6)=0

We add all the numbers together, and all the variables

9c+6(-3c-10)-(13c+6)=0

We multiply parentheses

9c-18c-(13c+6)-60=0

We get rid of parentheses

9c-18c-13c-6-60=0

We add all the numbers together, and all the variables

-22c-66=0

We move all terms containing c to the left, all other terms to the right

-22c=66

c=66/-22

c=-3

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