6(-3u+2)=12-18u

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Solution for 6(-3u+2)=12-18u equation:



6(-3u+2)=12-18u
We move all terms to the left:
6(-3u+2)-(12-18u)=0
We add all the numbers together, and all the variables
6(-3u+2)-(-18u+12)=0
We multiply parentheses
-18u-(-18u+12)+12=0
We get rid of parentheses
-18u+18u-12+12=0
We add all the numbers together, and all the variables
=0
u=0/1
u=0

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