6(-3v+1)=(5-2v-2)

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Solution for 6(-3v+1)=(5-2v-2) equation: 



6(-3v+1)=(5-2v-2)

We move all terms to the left:

6(-3v+1)-((5-2v-2))=0

We add all the numbers together, and all the variables

6(-3v+1)-((-2v+3))=0

We multiply parentheses

-18v-((-2v+3))+6=0



We calculate terms in parentheses: -((-2v+3)), so:

(-2v+3)

We get rid of parentheses

-2v+3

Back to the equation:

-(-2v+3)



We get rid of parentheses

-18v+2v-3+6=0

We add all the numbers together, and all the variables

-16v+3=0

We move all terms containing v to the left, all other terms to the right

-16v=-3

v=-3/-16

v=3/16

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