6(-3z+2)=-24

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Solution for 6(-3z+2)=-24 equation: 



6(-3z+2)=-24

We move all terms to the left:

6(-3z+2)-(-24)=0

We add all the numbers together, and all the variables

6(-3z+2)+24=0

We multiply parentheses

-18z+12+24=0

We add all the numbers together, and all the variables

-18z+36=0

We move all terms containing z to the left, all other terms to the right

-18z=-36

z=-36/-18

z=+2

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