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6(-5+x)=2(3x)
We move all terms to the left:
6(-5+x)-(2(3x))=0
determiningTheFunctionDomain 6(-5+x)-23x=0
We add all the numbers together, and all the variables
6(x-5)-23x=0
We add all the numbers together, and all the variables
-23x+6(x-5)=0
We multiply parentheses
-23x+6x-30=0
We add all the numbers together, and all the variables
-17x-30=0
We move all terms containing x to the left, all other terms to the right
-17x=30
x=30/-17
x=-1+13/17
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