6(-8+3b)=78

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Solution for 6(-8+3b)=78 equation: 



6(-8+3b)=78

We move all terms to the left:

6(-8+3b)-(78)=0

We add all the numbers together, and all the variables

6(3b-8)-78=0

We multiply parentheses

18b-48-78=0

We add all the numbers together, and all the variables

18b-126=0

We move all terms containing b to the left, all other terms to the right

18b=126

b=126/18

b=7

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