6(-8-2b)=12

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Solution for 6(-8-2b)=12 equation:



6(-8-2b)=12
We move all terms to the left:
6(-8-2b)-(12)=0
We add all the numbers together, and all the variables
6(-2b-8)-12=0
We multiply parentheses
-12b-48-12=0
We add all the numbers together, and all the variables
-12b-60=0
We move all terms containing b to the left, all other terms to the right
-12b=60
b=60/-12
b=-5

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