6(-b-5)-3(4b+2)=-b+14-2b

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Solution for 6(-b-5)-3(4b+2)=-b+14-2b equation: 



6(-b-5)-3(4b+2)=-b+14-2b

We move all terms to the left:

6(-b-5)-3(4b+2)-(-b+14-2b)=0

We add all the numbers together, and all the variables

6(-1b-5)-3(4b+2)-(-3b+14)=0

We multiply parentheses

-6b-12b-(-3b+14)-30-6=0

We get rid of parentheses

-6b-12b+3b-14-30-6=0

We add all the numbers together, and all the variables

-15b-50=0

We move all terms containing b to the left, all other terms to the right

-15b=50

b=50/-15

b=-3+1/3

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