6(-x-2)+12=4(x+3)-1

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Solution for 6(-x-2)+12=4(x+3)-1 equation: 



6(-x-2)+12=4(x+3)-1

We move all terms to the left:

6(-x-2)+12-(4(x+3)-1)=0

We add all the numbers together, and all the variables

6(-1x-2)-(4(x+3)-1)+12=0

We multiply parentheses

-6x-(4(x+3)-1)-12+12=0



We calculate terms in parentheses: -(4(x+3)-1), so:

4(x+3)-1

We multiply parentheses

4x+12-1

We add all the numbers together, and all the variables

4x+11

Back to the equation:

-(4x+11)



We add all the numbers together, and all the variables

-6x-(4x+11)=0

We get rid of parentheses

-6x-4x-11=0

We add all the numbers together, and all the variables

-10x-11=0

We move all terms containing x to the left, all other terms to the right

-10x=11

x=11/-10

x=-1+1/10

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