6(-x-4)+3x=2(2x-9)+8

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Solution for 6(-x-4)+3x=2(2x-9)+8 equation: 



6(-x-4)+3x=2(2x-9)+8

We move all terms to the left:

6(-x-4)+3x-(2(2x-9)+8)=0

We add all the numbers together, and all the variables

6(-1x-4)+3x-(2(2x-9)+8)=0

We add all the numbers together, and all the variables

3x+6(-1x-4)-(2(2x-9)+8)=0

We multiply parentheses

3x-6x-(2(2x-9)+8)-24=0



We calculate terms in parentheses: -(2(2x-9)+8), so:

2(2x-9)+8

We multiply parentheses

4x-18+8

We add all the numbers together, and all the variables

4x-10

Back to the equation:

-(4x-10)



We add all the numbers together, and all the variables

-3x-(4x-10)-24=0

We get rid of parentheses

-3x-4x+10-24=0

We add all the numbers together, and all the variables

-7x-14=0

We move all terms containing x to the left, all other terms to the right

-7x=14

x=14/-7

x=-2

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