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6(1+1/2x)=2(x+1)
We move all terms to the left:
6(1+1/2x)-(2(x+1))=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
6(1/2x+1)-(2(x+1))=0
We multiply parentheses
6x-(2(x+1))+6=0
We calculate terms in parentheses: -(2(x+1)), so:We get rid of parentheses
2(x+1)
We multiply parentheses
2x+2
Back to the equation:
-(2x+2)
6x-2x-2+6=0
We add all the numbers together, and all the variables
4x+4=0
We move all terms containing x to the left, all other terms to the right
4x=-4
x=-4/4
x=-1
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