6(1+2k)-6k=-3(8k+4)

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Solution for 6(1+2k)-6k=-3(8k+4) equation: 



6(1+2k)-6k=-3(8k+4)

We move all terms to the left:

6(1+2k)-6k-(-3(8k+4))=0

We add all the numbers together, and all the variables

6(2k+1)-6k-(-3(8k+4))=0

We add all the numbers together, and all the variables

-6k+6(2k+1)-(-3(8k+4))=0

We multiply parentheses

-6k+12k-(-3(8k+4))+6=0



We calculate terms in parentheses: -(-3(8k+4)), so:

-3(8k+4)

We multiply parentheses

-24k-12

Back to the equation:

-(-24k-12)



We add all the numbers together, and all the variables

6k-(-24k-12)+6=0

We get rid of parentheses

6k+24k+12+6=0

We add all the numbers together, and all the variables

30k+18=0

We move all terms containing k to the left, all other terms to the right

30k=-18

k=-18/30

k=-3/5

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