6(1+2m)=(8+20m)/2

Solution for 6(1+2m)=(8+20m)/2 equation:

6(1+2m)=(8+20m)/2

We move all terms to the left:

6(1+2m)-((8+20m)/2)=0

We add all the numbers together, and all the variables

6(2m+1)-((20m+8)/2)=0

We multiply parentheses

12m-((20m+8)/2)+6=0

We multiply all the terms by the denominator


12m*2)-((20m+8)+6*2)=0

We add all the numbers together, and all the variables

12m*2)-((20m+8)=0

Wy multiply elements

24m^2=0

a = 24; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·24·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{48}=0$