6(1+2r)+5(-3r+6)=48

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Solution for 6(1+2r)+5(-3r+6)=48 equation:



6(1+2r)+5(-3r+6)=48
We move all terms to the left:
6(1+2r)+5(-3r+6)-(48)=0
We add all the numbers together, and all the variables
6(2r+1)+5(-3r+6)-48=0
We multiply parentheses
12r-15r+6+30-48=0
We add all the numbers together, and all the variables
-3r-12=0
We move all terms containing r to the left, all other terms to the right
-3r=12
r=12/-3
r=-4

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