6(1+3b)+4=82

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Solution for 6(1+3b)+4=82 equation: 



6(1+3b)+4=82

We move all terms to the left:

6(1+3b)+4-(82)=0

We add all the numbers together, and all the variables

6(3b+1)+4-82=0

We add all the numbers together, and all the variables

6(3b+1)-78=0

We multiply parentheses

18b+6-78=0

We add all the numbers together, and all the variables

18b-72=0

We move all terms containing b to the left, all other terms to the right

18b=72

b=72/18

b=4

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