6(1+3b)-6=-4(-3b+1)-8

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Solution for 6(1+3b)-6=-4(-3b+1)-8 equation: 



6(1+3b)-6=-4(-3b+1)-8

We move all terms to the left:

6(1+3b)-6-(-4(-3b+1)-8)=0

We add all the numbers together, and all the variables

6(3b+1)-(-4(-3b+1)-8)-6=0

We multiply parentheses

18b-(-4(-3b+1)-8)+6-6=0



We calculate terms in parentheses: -(-4(-3b+1)-8), so:

-4(-3b+1)-8

We multiply parentheses

12b-4-8

We add all the numbers together, and all the variables

12b-12

Back to the equation:

-(12b-12)



We add all the numbers together, and all the variables

18b-(12b-12)=0

We get rid of parentheses

18b-12b+12=0

We add all the numbers together, and all the variables

6b+12=0

We move all terms containing b to the left, all other terms to the right

6b=-12

b=-12/6

b=-2

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