6(1+3m)=(-2m+5)-4

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Solution for 6(1+3m)=(-2m+5)-4 equation: 



6(1+3m)=(-2m+5)-4

We move all terms to the left:

6(1+3m)-((-2m+5)-4)=0

We add all the numbers together, and all the variables

6(3m+1)-((-2m+5)-4)=0

We multiply parentheses

18m-((-2m+5)-4)+6=0



We calculate terms in parentheses: -((-2m+5)-4), so:

(-2m+5)-4

We get rid of parentheses

-2m+5-4

We add all the numbers together, and all the variables

-2m+1

Back to the equation:

-(-2m+1)



We get rid of parentheses

18m+2m-1+6=0

We add all the numbers together, and all the variables

20m+5=0

We move all terms containing m to the left, all other terms to the right

20m=-5

m=-5/20

m=-1/4

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