6(1+3m)=(-2m+5)-4

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Solution for 6(1+3m)=(-2m+5)-4 equation:



6(1+3m)=(-2m+5)-4
We move all terms to the left:
6(1+3m)-((-2m+5)-4)=0
We add all the numbers together, and all the variables
6(3m+1)-((-2m+5)-4)=0
We multiply parentheses
18m-((-2m+5)-4)+6=0
We calculate terms in parentheses: -((-2m+5)-4), so:
(-2m+5)-4
We get rid of parentheses
-2m+5-4
We add all the numbers together, and all the variables
-2m+1
Back to the equation:
-(-2m+1)
We get rid of parentheses
18m+2m-1+6=0
We add all the numbers together, and all the variables
20m+5=0
We move all terms containing m to the left, all other terms to the right
20m=-5
m=-5/20
m=-1/4

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