6(1+3m)=-8(-2m+5)=4

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Solution for 6(1+3m)=-8(-2m+5)=4 equation: 



6(1+3m)=-8(-2m+5)=4

We move all terms to the left:

6(1+3m)-(-8(-2m+5))=0

We add all the numbers together, and all the variables

6(3m+1)-(-8(-2m+5))=0

We multiply parentheses

18m-(-8(-2m+5))+6=0



We calculate terms in parentheses: -(-8(-2m+5)), so:

-8(-2m+5)

We multiply parentheses

16m-40

Back to the equation:

-(16m-40)



We get rid of parentheses

18m-16m+40+6=0

We add all the numbers together, and all the variables

2m+46=0

We move all terms containing m to the left, all other terms to the right

2m=-46

m=-46/2

m=-23

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