6(1+3n)=-8(2n+5)-5

Solution for 6(1+3n)=-8(2n+5)-5 equation:

6(1+3n)=-8(2n+5)-5

We move all terms to the left:

6(1+3n)-(-8(2n+5)-5)=0

We add all the numbers together, and all the variables

6(3n+1)-(-8(2n+5)-5)=0

We multiply parentheses

18n-(-8(2n+5)-5)+6=0


We calculate terms in parentheses: -(-8(2n+5)-5), so:

-8(2n+5)-5

We multiply parentheses

-16n-40-5

We add all the numbers together, and all the variables

-16n-45

Back to the equation:

-(-16n-45)


We get rid of parentheses

18n+16n+45+6=0

We add all the numbers together, and all the variables

34n+51=0

We move all terms containing n to the left, all other terms to the right

34n=-51

n=-51/34

n=-1+1/2