6(1+3r)=2(10+-9)-4r

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Solution for 6(1+3r)=2(10+-9)-4r equation: 



6(1+3r)=2(10+-9)-4r

We move all terms to the left:

6(1+3r)-(2(10+-9)-4r)=0

We add all the numbers together, and all the variables

6(3r+1)-(21-4r)=0

We multiply parentheses

18r-(21-4r)+6=0

We get rid of parentheses

18r+4r-21+6=0

We add all the numbers together, and all the variables

22r-15=0

We move all terms containing r to the left, all other terms to the right

22r=15

r=15/22

r=15/22

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