6(1+3x)=-8(2x+5)

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Solution for 6(1+3x)=-8(2x+5) equation: 



6(1+3x)=-8(2x+5)

We move all terms to the left:

6(1+3x)-(-8(2x+5))=0

We add all the numbers together, and all the variables

6(3x+1)-(-8(2x+5))=0

We multiply parentheses

18x-(-8(2x+5))+6=0



We calculate terms in parentheses: -(-8(2x+5)), so:

-8(2x+5)

We multiply parentheses

-16x-40

Back to the equation:

-(-16x-40)



We get rid of parentheses

18x+16x+40+6=0

We add all the numbers together, and all the variables

34x+46=0

We move all terms containing x to the left, all other terms to the right

34x=-46

x=-46/34

x=-1+6/17

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