6(1+3x)=132

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Solution for 6(1+3x)=132 equation: 



6(1+3x)=132

We move all terms to the left:

6(1+3x)-(132)=0

We add all the numbers together, and all the variables

6(3x+1)-132=0

We multiply parentheses

18x+6-132=0

We add all the numbers together, and all the variables

18x-126=0

We move all terms containing x to the left, all other terms to the right

18x=126

x=126/18

x=7

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