6(1+3x)=2(10x-9)-4x

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Solution for 6(1+3x)=2(10x-9)-4x equation: 



6(1+3x)=2(10x-9)-4x

We move all terms to the left:

6(1+3x)-(2(10x-9)-4x)=0

We add all the numbers together, and all the variables

6(3x+1)-(2(10x-9)-4x)=0

We multiply parentheses

18x-(2(10x-9)-4x)+6=0



We calculate terms in parentheses: -(2(10x-9)-4x), so:

2(10x-9)-4x

We add all the numbers together, and all the variables

-4x+2(10x-9)

We multiply parentheses

-4x+20x-18

We add all the numbers together, and all the variables

16x-18

Back to the equation:

-(16x-18)



We get rid of parentheses

18x-16x+18+6=0

We add all the numbers together, and all the variables

2x+24=0

We move all terms containing x to the left, all other terms to the right

2x=-24

x=-24/2

x=-12

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