6(1+3x)=8(2x+5)-4

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Solution for 6(1+3x)=8(2x+5)-4 equation: 



6(1+3x)=8(2x+5)-4

We move all terms to the left:

6(1+3x)-(8(2x+5)-4)=0

We add all the numbers together, and all the variables

6(3x+1)-(8(2x+5)-4)=0

We multiply parentheses

18x-(8(2x+5)-4)+6=0



We calculate terms in parentheses: -(8(2x+5)-4), so:

8(2x+5)-4

We multiply parentheses

16x+40-4

We add all the numbers together, and all the variables

16x+36

Back to the equation:

-(16x+36)



We get rid of parentheses

18x-16x-36+6=0

We add all the numbers together, and all the variables

2x-30=0

We move all terms containing x to the left, all other terms to the right

2x=30

x=30/2

x=15

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