6(1+4k)=3(6k+12)+3k

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Solution for 6(1+4k)=3(6k+12)+3k equation: 



6(1+4k)=3(6k+12)+3k

We move all terms to the left:

6(1+4k)-(3(6k+12)+3k)=0

We add all the numbers together, and all the variables

6(4k+1)-(3(6k+12)+3k)=0

We multiply parentheses

24k-(3(6k+12)+3k)+6=0



We calculate terms in parentheses: -(3(6k+12)+3k), so:

3(6k+12)+3k

We add all the numbers together, and all the variables

3k+3(6k+12)

We multiply parentheses

3k+18k+36

We add all the numbers together, and all the variables

21k+36

Back to the equation:

-(21k+36)



We get rid of parentheses

24k-21k-36+6=0

We add all the numbers together, and all the variables

3k-30=0

We move all terms containing k to the left, all other terms to the right

3k=30

k=30/3

k=10

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