6(1+4m)=2(10m+3)

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Solution for 6(1+4m)=2(10m+3) equation: 



6(1+4m)=2(10m+3)

We move all terms to the left:

6(1+4m)-(2(10m+3))=0

We add all the numbers together, and all the variables

6(4m+1)-(2(10m+3))=0

We multiply parentheses

24m-(2(10m+3))+6=0



We calculate terms in parentheses: -(2(10m+3)), so:

2(10m+3)

We multiply parentheses

20m+6

Back to the equation:

-(20m+6)



We get rid of parentheses

24m-20m-6+6=0

We add all the numbers together, and all the variables

4m=0

m=0/4

m=0

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