6(1+4v)+(-11+v)=42

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Solution for 6(1+4v)+(-11+v)=42 equation: 



6(1+4v)+(-11+v)=42

We move all terms to the left:

6(1+4v)+(-11+v)-(42)=0

We add all the numbers together, and all the variables

6(4v+1)+(v-11)-42=0

We multiply parentheses

24v+(v-11)+6-42=0

We get rid of parentheses

24v+v-11+6-42=0

We add all the numbers together, and all the variables

25v-47=0

We move all terms containing v to the left, all other terms to the right

25v=47

v=47/25

v=1+22/25

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