6(1+4v)+4v(-11-v)=42

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Solution for 6(1+4v)+4v(-11-v)=42 equation: 



6(1+4v)+4v(-11-v)=42

We move all terms to the left:

6(1+4v)+4v(-11-v)-(42)=0

We add all the numbers together, and all the variables

6(4v+1)+4v(-1v-11)-42=0

We multiply parentheses

-4v^2+24v-44v+6-42=0

We add all the numbers together, and all the variables

-4v^2-20v-36=0

a = -4; b = -20; c = -36;
Δ = b2-4ac
Δ = -202-4·(-4)·(-36)
Δ = -176
Delta is less than zero, so there is no solution for the equation

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