6(1+5y)=32y-2

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Solution for 6(1+5y)=32y-2 equation:



6(1+5y)=32y-2
We move all terms to the left:
6(1+5y)-(32y-2)=0
We add all the numbers together, and all the variables
6(5y+1)-(32y-2)=0
We multiply parentheses
30y-(32y-2)+6=0
We get rid of parentheses
30y-32y+2+6=0
We add all the numbers together, and all the variables
-2y+8=0
We move all terms containing y to the left, all other terms to the right
-2y=-8
y=-8/-2
y=+4

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