6(1+8b)-1=-40+3b

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Solution for 6(1+8b)-1=-40+3b equation: 



6(1+8b)-1=-40+3b

We move all terms to the left:

6(1+8b)-1-(-40+3b)=0

We add all the numbers together, and all the variables

6(8b+1)-(3b-40)-1=0

We multiply parentheses

48b-(3b-40)+6-1=0

We get rid of parentheses

48b-3b+40+6-1=0

We add all the numbers together, and all the variables

45b+45=0

We move all terms containing b to the left, all other terms to the right

45b=-45

b=-45/45

b=-1

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