6(1+c)=5(c-2)

Solution for 6(1+c)=5(c-2) equation:

Simplifying
6(1 + c) = 5(c + -2)
(1 * 6 + c * 6) = 5(c + -2)
(6 + 6c) = 5(c + -2)

Reorder the terms:
6 + 6c = 5(-2 + c)
6 + 6c = (-2 * 5 + c * 5)
6 + 6c = (-10 + 5c)

Solving
6 + 6c = -10 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
6 + 6c + -5c = -10 + 5c + -5c

Combine like terms: 6c + -5c = 1c
6 + 1c = -10 + 5c + -5c

Combine like terms: 5c + -5c = 0
6 + 1c = -10 + 0
6 + 1c = -10

Add '-6' to each side of the equation.
6 + -6 + 1c = -10 + -6

Combine like terms: 6 + -6 = 0
0 + 1c = -10 + -6
1c = -10 + -6

Combine like terms: -10 + -6 = -16
1c = -16

Divide each side by '1'.
c = -16

Simplifying
c = -16