6(1+n)=3+3(4n-5)

Solution for 6(1+n)=3+3(4n-5) equation:

6(1+n)=3+3(4n-5)

We move all terms to the left:

6(1+n)-(3+3(4n-5))=0

We add all the numbers together, and all the variables

6(n+1)-(3+3(4n-5))=0

We multiply parentheses

6n-(3+3(4n-5))+6=0


We calculate terms in parentheses: -(3+3(4n-5)), so:

3+3(4n-5)

determiningTheFunctionDomain
3(4n-5)+3

We multiply parentheses

12n-15+3

We add all the numbers together, and all the variables

12n-12

Back to the equation:

-(12n-12)


We get rid of parentheses

6n-12n+12+6=0

We add all the numbers together, and all the variables

-6n+18=0

We move all terms containing n to the left, all other terms to the right

-6n=-18

n=-18/-6

n=+3