6(1+x)=12(x-10)

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Solution for 6(1+x)=12(x-10) equation:



6(1+x)=12(x-10)
We move all terms to the left:
6(1+x)-(12(x-10))=0
We add all the numbers together, and all the variables
6(x+1)-(12(x-10))=0
We multiply parentheses
6x-(12(x-10))+6=0
We calculate terms in parentheses: -(12(x-10)), so:
12(x-10)
We multiply parentheses
12x-120
Back to the equation:
-(12x-120)
We get rid of parentheses
6x-12x+120+6=0
We add all the numbers together, and all the variables
-6x+126=0
We move all terms containing x to the left, all other terms to the right
-6x=-126
x=-126/-6
x=+21

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