6(1-12b)=-7(10b+4)

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Solution for 6(1-12b)=-7(10b+4) equation: 



6(1-12b)=-7(10b+4)

We move all terms to the left:

6(1-12b)-(-7(10b+4))=0

We add all the numbers together, and all the variables

6(-12b+1)-(-7(10b+4))=0

We multiply parentheses

-72b-(-7(10b+4))+6=0



We calculate terms in parentheses: -(-7(10b+4)), so:

-7(10b+4)

We multiply parentheses

-70b-28

Back to the equation:

-(-70b-28)



We get rid of parentheses

-72b+70b+28+6=0

We add all the numbers together, and all the variables

-2b+34=0

We move all terms containing b to the left, all other terms to the right

-2b=-34

b=-34/-2

b=+17

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