6(1-4a)+5a=-5(2+7a)

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Solution for 6(1-4a)+5a=-5(2+7a) equation: 



6(1-4a)+5a=-5(2+7a)

We move all terms to the left:

6(1-4a)+5a-(-5(2+7a))=0

We add all the numbers together, and all the variables

6(-4a+1)+5a-(-5(7a+2))=0

We add all the numbers together, and all the variables

5a+6(-4a+1)-(-5(7a+2))=0

We multiply parentheses

5a-24a-(-5(7a+2))+6=0



We calculate terms in parentheses: -(-5(7a+2)), so:

-5(7a+2)

We multiply parentheses

-35a-10

Back to the equation:

-(-35a-10)



We add all the numbers together, and all the variables

-19a-(-35a-10)+6=0

We get rid of parentheses

-19a+35a+10+6=0

We add all the numbers together, and all the variables

16a+16=0

We move all terms containing a to the left, all other terms to the right

16a=-16

a=-16/16

a=-1

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