6(1-4r)+3r+6=-3(3r-2)-6r

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Solution for 6(1-4r)+3r+6=-3(3r-2)-6r equation: 



6(1-4r)+3r+6=-3(3r-2)-6r

We move all terms to the left:

6(1-4r)+3r+6-(-3(3r-2)-6r)=0

We add all the numbers together, and all the variables

6(-4r+1)+3r-(-3(3r-2)-6r)+6=0

We add all the numbers together, and all the variables

3r+6(-4r+1)-(-3(3r-2)-6r)+6=0

We multiply parentheses

3r-24r-(-3(3r-2)-6r)+6+6=0



We calculate terms in parentheses: -(-3(3r-2)-6r), so:

-3(3r-2)-6r

We add all the numbers together, and all the variables

-6r-3(3r-2)

We multiply parentheses

-6r-9r+6

We add all the numbers together, and all the variables

-15r+6

Back to the equation:

-(-15r+6)



We add all the numbers together, and all the variables

-21r-(-15r+6)+12=0

We get rid of parentheses

-21r+15r-6+12=0

We add all the numbers together, and all the variables

-6r+6=0

We move all terms containing r to the left, all other terms to the right

-6r=-6

r=-6/-6

r=1

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