6(1-4x)+7(2+5x)=40

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Solution for 6(1-4x)+7(2+5x)=40 equation: 



6(1-4x)+7(2+5x)=40

We move all terms to the left:

6(1-4x)+7(2+5x)-(40)=0

We add all the numbers together, and all the variables

6(-4x+1)+7(5x+2)-40=0

We multiply parentheses

-24x+35x+6+14-40=0

We add all the numbers together, and all the variables

11x-20=0

We move all terms containing x to the left, all other terms to the right

11x=20

x=20/11

x=1+9/11

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