6(1-4x)-2(1+3x)=64

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Solution for 6(1-4x)-2(1+3x)=64 equation: 



6(1-4x)-2(1+3x)=64

We move all terms to the left:

6(1-4x)-2(1+3x)-(64)=0

We add all the numbers together, and all the variables

6(-4x+1)-2(3x+1)-64=0

We multiply parentheses

-24x-6x+6-2-64=0

We add all the numbers together, and all the variables

-30x-60=0

We move all terms containing x to the left, all other terms to the right

-30x=60

x=60/-30

x=-2

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