6(1-x)=8(1+2x)+2

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Solution for 6(1-x)=8(1+2x)+2 equation: 



6(1-x)=8(1+2x)+2

We move all terms to the left:

6(1-x)-(8(1+2x)+2)=0

We add all the numbers together, and all the variables

6(-1x+1)-(8(2x+1)+2)=0

We multiply parentheses

-6x-(8(2x+1)+2)+6=0



We calculate terms in parentheses: -(8(2x+1)+2), so:

8(2x+1)+2

We multiply parentheses

16x+8+2

We add all the numbers together, and all the variables

16x+10

Back to the equation:

-(16x+10)



We get rid of parentheses

-6x-16x-10+6=0

We add all the numbers together, and all the variables

-22x-4=0

We move all terms containing x to the left, all other terms to the right

-22x=4

x=4/-22

x=-2/11

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