6(1/2b+3)+4(12-b)=5/6

Solution for 6(1/2b+3)+4(12-b)=5/6 equation:

6(1/2b+3)+4(12-b)=5/6

We move all terms to the left:

6(1/2b+3)+4(12-b)-(5/6)=0


Domain of the equation: 2b+3)!=0

b∈R


We add all the numbers together, and all the variables

6(1/2b+3)+4(-1b+12)-(+5/6)=0

We multiply parentheses

6b-4b+18+48-(+5/6)=0

We get rid of parentheses

6b-4b+18+48-5/6=0

We multiply all the terms by the denominator


6b*6-4b*6-5+18*6+48*6=0

We add all the numbers together, and all the variables

6b*6-4b*6+391=0

Wy multiply elements

36b-24b+391=0

We add all the numbers together, and all the variables

12b+391=0

We move all terms containing b to the left, all other terms to the right

12b=-391

b=-391/12

b=-32+7/12