6(1/3-y)=(7/5+15y)

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Solution for 6(1/3-y)=(7/5+15y) equation: 



6(1/3-y)=(7/5+15y)

We move all terms to the left:

6(1/3-y)-((7/5+15y))=0



Domain of the equation: 3-y)!=0

We move all terms containing y to the left, all other terms to the right

-y)!=-3

y!=-3/1

y!=-3

y∈R





Domain of the equation: 5+15y))!=0

We move all terms containing y to the left, all other terms to the right

15y))!=-5

y!=-5/1

y!=-5

y∈R



We add all the numbers together, and all the variables

6(-1y+1/3)-((+15y+7/5))=0

We multiply parentheses

-6y-((+15y+7/5))+1/3*6=0

We calculate fractions


-6y+(-((+15y+7*3*6)/()+()/()=0



We calculate terms in parentheses: +(-((+15y+7*3*6)/()+()/(), so:

-((+15y+7*3*6)/()+()/(

We can not solve this equation

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