6(1/6x-2)=4(1-2x)+3

Solution for 6(1/6x-2)=4(1-2x)+3 equation:

6(1/6x-2)=4(1-2x)+3

We move all terms to the left:

6(1/6x-2)-(4(1-2x)+3)=0


Domain of the equation: 6x-2)!=0

x∈R


We add all the numbers together, and all the variables

6(1/6x-2)-(4(-2x+1)+3)=0

We multiply parentheses

6x-(4(-2x+1)+3)-12=0


We calculate terms in parentheses: -(4(-2x+1)+3), so:

4(-2x+1)+3

We multiply parentheses

-8x+4+3

We add all the numbers together, and all the variables

-8x+7

Back to the equation:

-(-8x+7)


We get rid of parentheses

6x+8x-7-12=0

We add all the numbers together, and all the variables

14x-19=0

We move all terms containing x to the left, all other terms to the right

14x=19

x=19/14

x=1+5/14