6(10+2y)=168

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Solution for 6(10+2y)=168 equation: 



6(10+2y)=168

We move all terms to the left:

6(10+2y)-(168)=0

We add all the numbers together, and all the variables

6(2y+10)-168=0

We multiply parentheses

12y+60-168=0

We add all the numbers together, and all the variables

12y-108=0

We move all terms containing y to the left, all other terms to the right

12y=108

y=108/12

y=9

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