6(10-4x)=45-5(4x+1)

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Solution for 6(10-4x)=45-5(4x+1) equation:



6(10-4x)=45-5(4x+1)
We move all terms to the left:
6(10-4x)-(45-5(4x+1))=0
We add all the numbers together, and all the variables
6(-4x+10)-(45-5(4x+1))=0
We multiply parentheses
-24x-(45-5(4x+1))+60=0
We calculate terms in parentheses: -(45-5(4x+1)), so:
45-5(4x+1)
determiningTheFunctionDomain -5(4x+1)+45
We multiply parentheses
-20x-5+45
We add all the numbers together, and all the variables
-20x+40
Back to the equation:
-(-20x+40)
We get rid of parentheses
-24x+20x-40+60=0
We add all the numbers together, and all the variables
-4x+20=0
We move all terms containing x to the left, all other terms to the right
-4x=-20
x=-20/-4
x=+5

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