6(10-8y)+4y=28

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Solution for 6(10-8y)+4y=28 equation: 



6(10-8y)+4y=28

We move all terms to the left:

6(10-8y)+4y-(28)=0

We add all the numbers together, and all the variables

6(-8y+10)+4y-28=0

We add all the numbers together, and all the variables

4y+6(-8y+10)-28=0

We multiply parentheses

4y-48y+60-28=0

We add all the numbers together, and all the variables

-44y+32=0

We move all terms containing y to the left, all other terms to the right

-44y=-32

y=-32/-44

y=8/11

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